b^2-16b-161=0

Solution for b^2-16b-161=0 equation:

Simplifying
b2 + -16b + -161 = 0

Reorder the terms:
-161 + -16b + b2 = 0

Solving
-161 + -16b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(-7 + -1b)(23 + -1b) = 0

Subproblem 1
Set the factor '(-7 + -1b)' equal to zero and attempt to solve:

Simplifying
-7 + -1b = 0

Solving
-7 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '7' to each side of the equation.
-7 + 7 + -1b = 0 + 7

Combine like terms: -7 + 7 = 0
0 + -1b = 0 + 7
-1b = 0 + 7

Combine like terms: 0 + 7 = 7
-1b = 7

Divide each side by '-1'.
b = -7

Simplifying
b = -7
Subproblem 2
Set the factor '(23 + -1b)' equal to zero and attempt to solve:

Simplifying
23 + -1b = 0

Solving
23 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-23' to each side of the equation.
23 + -23 + -1b = 0 + -23

Combine like terms: 23 + -23 = 0
0 + -1b = 0 + -23
-1b = 0 + -23

Combine like terms: 0 + -23 = -23
-1b = -23

Divide each side by '-1'.
b = 23

Simplifying
b = 23
Solution
b = {-7, 23}